Two periodic waves of intensities I_{1} and I | vedclass

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(D) The resultant intensity of two periodic waves is given by the formula:$I = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}}\cos\delta$where $\delta$ is the phas

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$2(I_{1}+I_{2})$

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(D) The resultant intensity of two periodic waves is given by the formula:$I = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}}\cos\delta$where $\delta$ is the phase difference between the waves.For maximum intensity,$\cos\delta = 1$,so:$I_{\max} = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}} = (\sqrt{I_{1}} + \sqrt{I_{2}})^{2}$For minimum intensity,$\cos\delta = -1$,so:$I_{\min} = I_{1} + I_{2} - 2\sqrt{I_{1}I_{2}} = (\sqrt{I_{1}} - \sqrt{I_{2}})^{2}$The sum of the maximum and minimum intensities is:$I_{\max} + I_{\min} = (\sqrt{I_{1}} + \sqrt{I_{2}})^{2} + (\sqrt{I_{1}} - \sqrt{I_{2}})^{2}$Expanding the squares:$I_{\max} + I_{\min} = (I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}}) + (I_{1} + I_{2} - 2\sqrt{I_{1}I_{2}})$$I_{\max} + I_{\min} = 2(I_{1} + I_{2})$

Two periodic waves of intensities $I_{1}$ and $I_{2}$ pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is

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