If vec{A} = 3hat{i} + 4hat{j} and vec{B} = 6h | vedclass

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(C) Given $\vec{A} = 3\hat{i} + 4\hat{j}$ and $\vec{B} = 6\hat{i} + 8\hat{j}$.Magnitudes are $A = \sqrt{3^2 + 4^2} = 5$ and $B = \sqrt{6^2 + 8^2} = 10

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$\vec{A} \cdot \vec{B} = 40$

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(C) Given $\vec{A} = 3\hat{i} + 4\hat{j}$ and $\vec{B} = 6\hat{i} + 8\hat{j}$.Magnitudes are $A = \sqrt{3^2 + 4^2} = 5$ and $B = \sqrt{6^2 + 8^2} = 10$.Check option $(A)$: $\vec{A} 	imes \vec{B} = (3\hat{i} + 4\hat{j}) 	imes (6\hat{i} + 8\hat{j}) = (3 	imes 8 - 4 	imes 6)\hat{k} = (24 - 24)\hat{k} = 0$. This is correct.Check option $(B)$: $\frac{A}{B} = \frac{5}{10} = \frac{1}{2}$. This is correct.Check option $(C)$: $\vec{A} \cdot \vec{B} = (3)(6) + (4)(8) = 18 + 32 = 50$. The option states $40$,which is incorrect.Therefore,the incorrect statement is option $(C)$.

If $\vec{A} = 3\hat{i} + 4\hat{j}$ and $\vec{B} = 6\hat{i} + 8\hat{j}$,where $A$ and $B$ are the magnitudes of vectors $\vec{A}$ and $\vec{B}$ respectively,which of the following is incorrect?

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