The resultant of two vectors $\overrightarrow{P}$ and $\overrightarrow{Q}$ is $\overrightarrow{R}$. If $\overrightarrow{Q}$ is doubled,the new resultant is perpendicular to $\overrightarrow{P}$. Then $R$ equals

If $\vec{A} = 3\hat{i} + 4\hat{j}$ and $\vec{B} = 6\hat{i} + 8\hat{j}$,where $A$ and $B$ are the magnitudes of vectors $\vec{A}$ and $\vec{B}$ respectively,which of the following is incorrect?

If $P = Q = R$ and $\vec{P} + \vec{Q} = \vec{R}$,let $\theta_1$ be the angle between $\vec{P}$ and $\vec{R}$. If $\vec{P} + \vec{Q} + \vec{R} = \vec{0}$,let $\theta_2$ be the angle between $\vec{P}$ and $\vec{R}$. What is the relationship between $\theta_1$ and $\theta_2$?

If $\theta$ is the angle between two vectors $\vec{A}$ and $\vec{B}$,then match the following two columns.

Column $I$	Column $II$
$(A)$ $\vec{A} \cdot \vec{B} = |\vec{A} \times \vec{B}|$	$(p)$ $\theta = 45^{\circ}$ or $135^{\circ}$
$(B)$ $\vec{A} \cdot \vec{B} = B^2$	$(q)$ $\theta = 0^{\circ}$
$(C)$ $|\vec{A} + \vec{B}| = |\vec{A} - \vec{B}|$	$(r)$ $\vec{A} = \vec{B}$
$(D)$ $|\vec{A} \times \vec{B}| = AB$	$(s)$ $\theta = 90^{\circ}$

Match Column-$I$ with Column-$II$.

Column-$I$	Column-$II$
$(1)$ Resultant of two mutually perpendicular vectors	$(a)$ Along the bisector of the angle between them
$(2)$ Direction of $\overrightarrow A \times \overrightarrow B$	$(b)$ Coplanar
	$(c)$ Perpendicular to the plane containing $\overrightarrow A$ and $\overrightarrow B$

The three vectors $\vec{A}=3 \hat{i}-2 \hat{j}+\hat{k}$,$\vec{B}=\hat{i}-3 \hat{j}+5 \hat{k}$ and $\vec{C}=2 \hat{i}-\hat{j}+4 \hat{k}$ will form