What is the value of (vec{A} + vec{B}) cdot ( | vedclass

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(A) The expression is $(\vec{A} + \vec{B}) \cdot (\vec{A} 	imes \vec{B})$.Using the distributive property of the dot product over addition,we get:$(\

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$0$

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(A) The expression is $(\vec{A} + \vec{B}) \cdot (\vec{A} 	imes \vec{B})$.Using the distributive property of the dot product over addition,we get:$(\vec{A} + \vec{B}) \cdot (\vec{A} 	imes \vec{B}) = \vec{A} \cdot (\vec{A} 	imes \vec{B}) + \vec{B} \cdot (\vec{A} 	imes \vec{B})$.The term $\vec{A} \cdot (\vec{A} 	imes \vec{B})$ represents the scalar triple product of vectors $\vec{A}, \vec{A},$ and $\vec{B}$. Since two vectors are identical,the volume of the parallelepiped formed is zero,so $\vec{A} \cdot (\vec{A} 	imes \vec{B}) = 0$.Similarly,$\vec{B} \cdot (\vec{A} 	imes \vec{B})$ represents the scalar triple product of vectors $\vec{B}, \vec{A},$ and $\vec{B}$. Since two vectors are identical,$\vec{B} \cdot (\vec{A} 	imes \vec{B}) = 0$.Therefore,the total value is $0 + 0 = 0$.

What is the value of $(\vec{A} + \vec{B}) \cdot (\vec{A} \times \vec{B})$?

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