A thin biconvex lens is made of glass (mu = 1 | vedclass

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(B) The lens maker's formula is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.Given: $\mu = 1.5$,$R_1 = +20 \ cm$,a

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$20$

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(B) The lens maker's formula is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.Given: $\mu = 1.5$,$R_1 = +20 \ cm$,and $R_2 = -20 \ cm$.Substituting the values: $\frac{1}{f} = (1.5 - 1) \left( \frac{1}{20} - \frac{1}{-20} \right)$.$\frac{1}{f} = (0.5) \left( \frac{1}{20} + \frac{1}{20} \right) = (0.5) \left( \frac{2}{20} \right) = (0.5) \left( \frac{1}{10} \right) = \frac{1}{20}$.Therefore,$f = 20 \ cm$.Since the incident light is parallel to the principal axis,the rays converge at the focal point. Thus,$L = f = 20 \ cm$.

$A$ thin biconvex lens is made of glass $(\mu = 1.50)$ and both surfaces have a radius of curvature of $20 \ cm$. $A$ beam of incident light is parallel to the principal axis of the lens. The lens converges it at a distance $L \ cm$. Then $L = \dots$

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