For a common emitter amplifier,the voltage gain is $50$,the input resistance is $200 \ \Omega$,and the output resistance is $400 \ \Omega$. The power gain of the amplifier will be:

In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5\,V$, the collector current changes by $0.05\,mA$. The output resistance will be....$k\Omega$.

In a transistor,if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$,then the value of $\beta$ lies between:

$A$ transistor is connected in a common emitter configuration with $R_o = 4 \text{ k}\Omega$,$R_i = 1 \text{ k}\Omega$,$I_C = 1 \text{ mA}$,and $I_b = 20 \text{ }\mu\text{A}$. The voltage gain is:

In which section of a transistor is the doping concentration highest to produce a large number of majority charge carriers?

$A$ common emitter transistor amplifier is connected with a load resistance of $6 k\Omega$. When a small a.c. signal of $15 mV$ is added to the base-emitter voltage, the alternating base current is $20 \mu A$ and the alternating collector current is $1.8 mA$. What is the voltage gain of the amplifier?