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(A) The output resistance $(R_{out})$ in $CB$ mode is defined as the ratio of the change in collector voltage $(\Delta V_C)$ to the change in collecto

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$10$

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(A) The output resistance $(R_{out})$ in $CB$ mode is defined as the ratio of the change in collector voltage $(\Delta V_C)$ to the change in collector current $(\Delta I_C)$ while keeping the emitter current constant.Given: $\Delta V_C = 0.5\,V$ and $\Delta I_C = 0.05\,mA = 0.05 	imes 10^{-3}\,A$.Using the formula: $R_{out} = \frac{\Delta V_C}{\Delta I_C}$.Substituting the values: $R_{out} = \frac{0.5}{0.05 	imes 10^{-3}} = \frac{0.5}{5 	imes 10^{-5}} = 0.1 	imes 10^5 = 10^4\,\Omega$.Since $10^4\,\Omega = 10 	imes 10^3\,\Omega = 10\,k\Omega$.Therefore, the output resistance is $10\,k\Omega$.

In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5\,V$, the collector current changes by $0.05\,mA$. The output resistance will be....$k\Omega$.

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