If $\alpha$ is the current gain in a $CB$ circuit and $\beta$ is the current gain in a $CE$ circuit,then $\alpha / \beta$ = ......

The given transistor amplifier connection is

In a common emitter transistor amplifier circuit,the input resistance is $1.8 \text{ k}\Omega$ and the output is obtained across a load resistance of $9 \text{ k}\Omega$. The alternating current gain is $70$. Corresponding to an a.c. input voltage of $6 \text{ mV}$,the output voltage will be: (in $\text{ V}$)

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

$A$ $N-P-N$ transistor is connected in common emitter configuration (see figure) in which the collector voltage drop across the load resistance $(800 \; \Omega)$ connected to the collector circuit is $0.8 \; V$. The collector current is .............. $mA$.

The current gain $\beta$ of a transistor is $50$. The input resistance of the transistor when used in the common emitter mode is $1\,k\Omega$. The peak value of the collector current for an input peak voltage of $0.01\,V$ is ...... $\mu A$.