Two conducting spheres of radii 20, cm and 15 | vedclass

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(C) When two conductors are connected by a wire,charge flows until their potentials become equal $(V_1 = V_2)$.Since the potential of a spherical cond

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The surface charge density will be lower on the sphere of radius $20\, cm$.

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(C) When two conductors are connected by a wire,charge flows until their potentials become equal $(V_1 = V_2)$.Since the potential of a spherical conductor is $V = \frac{kQ}{r}$,the final charges $Q_1'$ and $Q_2'$ will be proportional to their radii $(Q \propto r)$.The surface charge density is given by $\sigma = \frac{Q}{A} = \frac{Q}{4\pi r^2}$.Substituting $Q \propto r$,we get $\sigma \propto \frac{r}{r^2} = \frac{1}{r}$.Since $\sigma \propto \frac{1}{r}$,the sphere with the larger radius $(20\, cm)$ will have a lower surface charge density compared to the sphere with the smaller radius $(15\, cm)$.

Two conducting spheres of radii $20\, cm$ and $15\, cm$ are placed on insulating stands. Both are given an equal charge of $10\ \mu C$. When they are connected by a copper wire and then disconnected,which of the following is true?

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