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(B) When $n$ capacitors,each of capacitance $C$,are connected in parallel to a voltage source $V$,the potential difference across each capacitor is $V

Vedclass · Accepted Answer

$\frac{1}{2}nCV^2$

Vedclass · Answer

(B) When $n$ capacitors,each of capacitance $C$,are connected in parallel to a voltage source $V$,the potential difference across each capacitor is $V$.The energy stored in a single capacitor is given by $U_i = \frac{1}{2}CV^2$.Since the capacitors are in parallel,the total energy $U$ is the sum of the energies stored in each individual capacitor:$U = U_1 + U_2 + ... + U_n$$U = \frac{1}{2}CV^2 + \frac{1}{2}CV^2 + ... + \frac{1}{2}CV^2$ ($n$ times)$U = n 	imes (\frac{1}{2}CV^2)$$U = \frac{1}{2}nCV^2$.

If $n$ capacitors are connected in parallel with a source of $V$ volts,the stored energy is equal to ........

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