બે સમાન બિંદુવત વિદ્યુતભાર q ને જોડતી રેખાના | vedclass

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Question

Step $1:$ Equilibrium of central charge $Q$ [Ref. Fig. $1$]

For the system to be in equilibrium net force on each charge should be zero.

By Symm

Vedclass · Accepted Answer

$-Q/4$

Vedclass · Answer

Step $1:$ Equilibrium of central charge $Q$ [Ref. Fig. $1$]

For the system to be in equilibrium net force on each charge should be zero.

By Symmetry, both outer charges $q$ will exert equal and opposite force on $Q$, which will cancel out. As shown in Figure $1$.

Hence Net force on $Q$ will always be zero irrespective of value of charge.

Step $2:$ Equilibrium of outer charge $q$ [Ref. Fig. $2]$

Net force on charge $q$ at the right, due to other two charges should be zero.

$F_q=\frac{K Q q}{x^2}+\frac{K^2}{(2 x)^2}=0$

$\Rightarrow \frac{K Q q}{x^2}=-\frac{K^2}{4 x^2}$

$\Rightarrow Q=\frac{-q}{4}$

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