હવામાં ‘r’ અંતરે આવેલા બે બિંદુવત | vedclass

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Question

Two point charge placed at a certain distance $=r$

force $= F$

dielectric constant $= k$

Let, two point charges $q_1$ and $q_2$ are separated

Vedclass · Accepted Answer

$r/\sqrt K $

Vedclass · Answer

Two point charge placed at a certain distance $=r$

force $= F$

dielectric constant $= k$

Let, two point charges $q_1$ and $q_2$ are separated $r$ distance from each other.

Then, force experienced between then,

$F=\frac{q_1 q_2}{4 \pi \epsilon_0 r^2}$

Put, $F=\frac{q_1 q_2}{4 \pi \epsilon_0 r^2}$

$	herefore \frac{4 q_1 q_2}{4 \pi \epsilon_0 r ^2}=\frac{ q _1 q _2}{ k \left(4 \pi \epsilon_0 r ^2ight)}$

$\Rightarrow \frac{1}{ r ^2}=\frac{1}{4 r ^2 h }$

$\Rightarrow \frac{1}{ r ^2}=\frac{1}{ kr ^2}$

taking square root both sides

$\frac{1}{ r }-\frac{1}{\sqrt{ kr ^1}}$

or, $r ^1=\frac{ r }{\sqrt{ k }}$

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