An electron and a positron annihilate each ot | vedclass

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(B) The rest mass energy of an electron (or positron) is $E_0 = m_0 c^2 = 0.511 \, 	ext{MeV}$.Converting this to Joules: $E_0 = 0.511 	imes 10^6 \,

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$8.2 	imes 10^{-14} \, 	ext{J}$

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(B) The rest mass energy of an electron (or positron) is $E_0 = m_0 c^2 = 0.511 \, 	ext{MeV}$.Converting this to Joules: $E_0 = 0.511 	imes 10^6 \, 	ext{eV} 	imes 1.602 	imes 10^{-19} \, 	ext{J/eV} \approx 8.186 	imes 10^{-14} \, 	ext{J}$.Since the total energy of the electron-positron pair $(2 	imes 0.511 \, 	ext{MeV})$ is shared equally between two photons,the energy of each photon is equal to the rest mass energy of one particle.Therefore,the energy of each photon is $E = 8.2 	imes 10^{-14} \, 	ext{J}$.

An electron and a positron annihilate each other to produce two $\gamma$-ray photons of equal energy. The minimum energy of each photon is .....

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