The mass defect in a particular nuclear react | vedclass

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(D) Given mass defect,$\Delta m = 0.3 \,g = 0.3 	imes 10^{-3} \,kg = 3 	imes 10^{-4} \,kg$. Using Einstein's mass-energy equivalence principle,$E =

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$7.5 	imes 10^6$

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(D) Given mass defect,$\Delta m = 0.3 \,g = 0.3 	imes 10^{-3} \,kg = 3 	imes 10^{-4} \,kg$. Using Einstein's mass-energy equivalence principle,$E = \Delta m c^2$. Substituting the values,$E = (3 	imes 10^{-4} \,kg) 	imes (3 	imes 10^8 \,m/s)^2$. $E = 3 	imes 10^{-4} 	imes 9 	imes 10^{16} = 27 	imes 10^{12} \,J$. To convert Joules to kilowatt-hour $(kWh)$,we divide by $3.6 	imes 10^6 \,J/kWh$. $E = \frac{27 	imes 10^{12}}{3.6 	imes 10^6} \,kWh$. $E = 7.5 	imes 10^6 \,kWh$.

The mass defect in a particular nuclear reaction is $0.3 \,g$. The amount of energy liberated in kilowatt-hour $(kWh)$ is: (Velocity of light $c = 3 \times 10^8 \,m/s$)

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