If _{92}U^{238} to _{Z}X^{A} + _{2}He^{4},the | vedclass

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Question

(A) In an alpha decay process,the mass number decreases by $4$ and the atomic number decreases by $2$.Given the reaction: $_{92}U^{238} 	o _{Z}X^{A}

Vedclass · Accepted Answer

$90, 234$

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(A) In an alpha decay process,the mass number decreases by $4$ and the atomic number decreases by $2$.Given the reaction: $_{92}U^{238} 	o _{Z}X^{A} + _{2}He^{4}$.According to the law of conservation of mass number: $238 = A + 4 \implies A = 238 - 4 = 234$.According to the law of conservation of atomic number: $92 = Z + 2 \implies Z = 92 - 2 = 90$.Therefore,$Z = 90$ and $A = 234$.

If $_{92}U^{238} \to _{Z}X^{A} + _{2}He^{4}$,then $Z$ and $A$ will be ..........

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