The energy released per fission of uranium is $200 \, MeV$. How many fissions per second are required to produce a power of $2 \, MW$?

$A$ power of $100 \ W$ is produced by the fission of $1 \ kg$ of $^{235}U$. For approximately how long will the energy production continue?

$A$ $^{235}U$ nuclear reactor generates energy at a rate of $3.70 \times 10^7 \text{ J/s}$. Each fission liberates $185 \text{ MeV}$ of useful energy. If the reactor has to operate for $144 \times 10^4 \text{ s}$, the mass of the fuel needed is (Assume Avogadro's number $= 6 \times 10^{23} \text{ mol}^{-1}$, $1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$) (in $\text{ kg}$)

$113$. Energy released in the fission of a single uranium nucleus is $200 \text{ MeV}$. Then the number of fissions per second to produce $5 \text{ mW}$ power is

Kinetic energy of the emitted $\alpha-$ particle in the $\alpha-$ decay of ${}_{88}^{226}Ra$ will be,.......... $MeV$ (where $m_{\alpha} = 4.00260 \, u$,$m({}_{88}^{226}Ra) = 226.02540 \, u$ and $m({}_{86}^{222}Rn) = 222.01750 \, u$).

The control rod in a nuclear reactor is made of