$113$. Energy released in the fission of a single uranium nucleus is $200 \text{ MeV}$. Then the number of fissions per second to produce $5 \text{ mW}$ power is

  • A
    $1.56 \times 10^8$
  • B
    $1.56 \times 10^{13}$
  • C
    $3.12 \times 10^8$
  • D
    $3.12 \times 10^{13}$

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Similar Questions

Which of the following isotopes is normally fissionable?

What will be the energy released in joule,in the process of fission by $1 \text{ mg}$ of ${ }_{92}^{240} U$? Assume energy release per fission is $200 \text{ MeV}$. [Use Avogadro's number as $6 \times 10^{23}$ and $1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$]

In the proton-proton cycle in the Sun,the energy released when an electron and its antiparticle combine is $\qquad$ .

Consider the fission of $_{92}^{238} U$ by fast neutrons. In one fission event,no neutrons are emitted and the final end products,after the beta decay of the primary fragments,are $_{58}^{140} Ce$ and $_{44}^{99} Ru$. Calculate the $Q$-value for this fission process. The relevant atomic and particle masses are:
$m(_{92}^{238} U) = 238.05079 \; u$
$m(_{58}^{140} Ce) = 139.90543 \; u$
$m(_{44}^{99} Ru) = 98.90594 \; u$
$m(_{0}^{1} n) = 1.008665 \; u$

How much energy is released by the fusion of four hydrogen atoms to form a helium nucleus (in $MeV$)?

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