A ^{235}U nuclear reactor generates energy at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Total energy required $E = 	ext{Power} 	imes 	ext{Time} = (3.70 	imes 10^7 	ext{ J/s}) 	imes (144 	imes 10^4 	ext{ s}) = 5.328 	imes 10^{

Vedclass · Accepted Answer

$0.705$

Vedclass · Answer

(B) Total energy required $E = 	ext{Power} 	imes 	ext{Time} = (3.70 	imes 10^7 	ext{ J/s}) 	imes (144 	imes 10^4 	ext{ s}) = 5.328 	imes 10^{13} 	ext{ J}$.Energy per fission $\epsilon = 185 	ext{ MeV} = 185 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 2.96 	imes 10^{-11} 	ext{ J}$.Number of fissions required $N = \frac{E}{\epsilon} = \frac{5.328 	imes 10^{13}}{2.96 	imes 10^{-11}} = 1.8 	imes 10^{24} 	ext{ atoms}$.Mass of fuel $m = \frac{N 	imes M}{N_A} = \frac{1.8 	imes 10^{24} 	imes 235}{6 	imes 10^{23}} = 705 	ext{ g} = 0.705 	ext{ kg}$.

Similar Questions

The operation of a nuclear reactor is said to be critical if the multiplication factor $(K)$ has a value of:

The source of the Sun's energy is

If all the helium in a star is converted into oxygen in its core,the energy released per oxygen nucleus is...........$MeV$?
[Mass of $He = 4.0026 \, a.m.u.$,Mass of $O = 15.9994 \, a.m.u.$]

Which of the following statement$(s)$ is/are correct?

To generate a power of $3.2 \text{ MW}$,the number of fissions of $^{235}\text{U}$ per minute is (Energy released per fission $= 200 \text{ MeV}$,$1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module