In the Bohr model of the hydrogen atom,what i | vedclass

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(A) The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by the formula: $E_n = -\frac{13.6 \ eV}{n^2}$.For the ground state,$n

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$13.6$

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(A) The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by the formula: $E_n = -\frac{13.6 \ eV}{n^2}$.For the ground state,$n = 1$,so the energy is $E_1 = -13.6 \ eV$.To remove the electron from the atom (ionization),we need to provide enough energy to bring the electron to the state where $n = \infty$,where the energy is $E_{\infty} = 0 \ eV$.The energy required is $\Delta E = E_{\infty} - E_1 = 0 - (-13.6 \ eV) = 13.6 \ eV$.

In the Bohr model of the hydrogen atom,what is the energy required to remove an electron from the ground state $(n = 1)$ (in $eV$)?

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