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(D) The energy of an emitted photon is given by $\Delta E = E_{initial} - E_{final}$.Emission occurs when an electron transitions from a higher energy

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$IV$

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(D) The energy of an emitted photon is given by $\Delta E = E_{initial} - E_{final}$.Emission occurs when an electron transitions from a higher energy level to a lower energy level.Transitions $II$ and $IV$ represent emission.Transition $II$ is from $n=4$ to $n=3$,and transition $IV$ is from $n=4$ to $n=2$.The energy difference $\Delta E$ is proportional to the gap between the energy levels.Since the gap between $n=4$ and $n=2$ is larger than the gap between $n=4$ and $n=3$,transition $IV$ releases more energy than transition $II$.Therefore,transition $IV$ represents the emission of a photon with the most energy.

The diagram shows the energy levels for an electron in a certain atom. Which transition shown represents the emission of a photon with the most energy?

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