The energy levels with transitions for an ato | vedclass

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(A) The energy of a photon emitted during a transition is given by $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,a

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$A$,$D$

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(A) The energy of a photon emitted during a transition is given by $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is the wavelength.From this relation,we have $E \propto \frac{1}{\lambda}$.This means that for a transition to emit radiation of maximum wavelength,the energy difference $(E)$ must be minimum.For a transition to emit radiation of minimum wavelength,the energy difference $(E)$ must be maximum.Let's calculate the energy differences for the given transitions:Transition $A$: $\Delta E = 0 - (-2) = 2 	ext{ eV}$ (Minimum energy difference)Transition $B$: $\Delta E = 0 - (-4.5) = 4.5 	ext{ eV}$Transition $C$: $\Delta E = -2 - (-4.5) = 2.5 	ext{ eV}$Transition $D$: $\Delta E = -2 - (-10) = 8 	ext{ eV}$ (Maximum energy difference)Since transition $A$ has the minimum energy difference,it corresponds to the maximum wavelength.Since transition $D$ has the maximum energy difference,it corresponds to the minimum wavelength.Therefore,the transitions for maximum and minimum wavelength are $A$ and $D$ respectively.

The energy levels with transitions for an atom are shown in the figure. The transitions corresponding to the emission of radiation of maximum and minimum wavelength are respectively:

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