For very dilute solutions of BaCl_2 (t_1) and | vedclass

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Question

(B) The elevation in boiling point is a colligative property,which depends on the number of particles in the solution.$BaCl_2$ dissociates as $BaCl_2

Vedclass · Accepted Answer

$t_1 > t_2$

Vedclass · Answer

(B) The elevation in boiling point is a colligative property,which depends on the number of particles in the solution.$BaCl_2$ dissociates as $BaCl_2 \rightarrow Ba^{2+} + 2Cl^-$,producing $3$ ions per formula unit.$KCl$ dissociates as $KCl \rightarrow K^+ + Cl^-$,producing $2$ ions per formula unit.Since the molarity is the same,the van't Hoff factor $(i)$ for $BaCl_2$ $(i \approx 3)$ is greater than that for $KCl$ $(i \approx 2)$.Therefore,the elevation in boiling point for $BaCl_2$ is greater than that for $KCl$,implying $t_1 > t_2$.

For very dilute solutions of $BaCl_2$ $(t_1)$ and $KCl$ $(t_2)$ having the same molarity,what is the correct relationship between their boiling points?

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