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(D) The elevation in boiling point is given by the formula $\Delta T_b = i 	imes K_b 	imes m$. Since the concentration $(m)$ and the ebullioscopic c

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Ferric chloride

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(D) The elevation in boiling point is given by the formula $\Delta T_b = i 	imes K_b 	imes m$. Since the concentration $(m)$ and the ebullioscopic constant $(K_b)$ are the same for all solutions,the boiling point depends on the van't Hoff factor $(i)$,which represents the number of particles produced upon dissociation. $A$: Glucose $(C_6H_{12}O_6)$ is a non-electrolyte,so $i = 1$. $B$: Sodium chloride $(NaCl)$ dissociates as $NaCl ightarrow Na^+ + Cl^-$,so $i = 2$. $C$: Calcium chloride $(CaCl_2)$ dissociates as $CaCl_2 ightarrow Ca^{2+} + 2Cl^-$,so $i = 3$. $D$: Ferric chloride $(FeCl_3)$ dissociates as $FeCl_3 ightarrow Fe^{3+} + 3Cl^-$,so $i = 4$. Since Ferric chloride has the highest value of $i$,it will have the highest boiling point.

Identify the compound amongst the following whose $0.1 \ M$ aqueous solution has the highest boiling point.

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