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(A) $10\% (w/v)$ solution means $10 \, 	ext{g}$ of glucose is present in $100 \, 	ext{mL}$ of solution.The molar mass of glucose $(C_6H_{12}O_6)$ is

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$3.6$

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(A) $10\% (w/v)$ solution means $10 \, 	ext{g}$ of glucose is present in $100 \, 	ext{mL}$ of solution.The molar mass of glucose $(C_6H_{12}O_6)$ is $180 \, 	ext{g/mol}$.Mass of $2 \, 	ext{moles}$ of glucose $= 2 \, 	ext{mol} 	imes 180 \, 	ext{g/mol} = 360 \, 	ext{g}$.Since $10 \, 	ext{g}$ of glucose is in $100 \, 	ext{mL}$ of solution,then $360 \, 	ext{g}$ of glucose will be in:$	ext{Volume} = \frac{100 \, 	ext{mL}}{10 \, 	ext{g}} 	imes 360 \, 	ext{g} = 3600 \, 	ext{mL}$.Converting to liters: $3600 \, 	ext{mL} = 3.6 \, 	ext{L}$.

$A$ $10\% (w/v)$ aqueous solution of glucose is prepared. What is the volume in $litre$ of this solution that contains $2 \, \text{moles}$ of the solute?

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