A solution of a solute in benzene has a molal | vedclass

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(B) Molality $(X)$ is defined as the number of moles of solute per $1000 \ g$ of solvent. Given,mass of solvent (benzene,$C_6H_6$) = $1000 \ g$. Molar

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$3.2$

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(B) Molality $(X)$ is defined as the number of moles of solute per $1000 \ g$ of solvent. Given,mass of solvent (benzene,$C_6H_6$) = $1000 \ g$. Molar mass of benzene = $78 \ g/mol$. Moles of benzene = $\frac{1000}{78} \approx 12.82 \ mol$. Mole fraction of solute $(x_{solute})$ = $\frac{n_{solute}}{n_{solute} + n_{solvent}} = 0.2$. Let $n_{solute} = X$. $\frac{X}{X + 12.82} = 0.2$. $X = 0.2X + 2.564$. $0.8X = 2.564$. $X = \frac{2.564}{0.8} = 3.205 \approx 3.2$.

$A$ solution of a solute in benzene has a molality of $X \ m$. If the mole fraction of the solute is $0.2$,what is the value of $X$?

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