The molarity of the solution obtained by mixi | vedclass

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Question

(A) For $HCl$,the normality $(N)$ is equal to the molarity $(M)$ because the $n$-factor is $1$. Thus,$0.5 \ (N) \ HCl = 0.5 \ (M) \ HCl$. The formula

Vedclass · Accepted Answer

$0.87$

Vedclass · Answer

(A) For $HCl$,the normality $(N)$ is equal to the molarity $(M)$ because the $n$-factor is $1$. Thus,$0.5 \ (N) \ HCl = 0.5 \ (M) \ HCl$. The formula for the molarity of a mixture is $M_{mix} = \frac{M_1V_1 + M_2V_2}{V_1 + V_2}$. Here,$M_1 = 0.5 \ M$,$V_1 = 750 \ mL$,$M_2 = 2 \ M$,and $V_2 = 250 \ mL$. $M_{mix} = \frac{(0.5 	imes 750) + (2 	imes 250)}{750 + 250} = \frac{375 + 500}{1000} = \frac{875}{1000} = 0.875 \ M$. Rounding to two decimal places,the answer is $0.87 \ M$.

The molarity of the solution obtained by mixing $750 \ mL$ of $0.5 \ (N) \ HCl$ with $250 \ mL$ of $2 \ (M) \ HCl$ is ........... $M$.

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