Arrange the following 0.1 M salt solutions i | vedclass

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(B) To determine the $pH$ order,we analyze the nature of the salts:$1$. $HCl$ is a strong acid,so its $0.1 \ M$ solution has the lowest $pH$ (approx $

Vedclass · Accepted Answer

$HCl < NH_4Cl < NaCl < NaCN$

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(B) To determine the $pH$ order,we analyze the nature of the salts:$1$. $HCl$ is a strong acid,so its $0.1 \ M$ solution has the lowest $pH$ (approx $1$).$2$. $NH_4Cl$ is a salt of a strong acid $(HCl)$ and a weak base $(NH_4OH)$,making it acidic $(pH $3$. $NaCl$ is a salt of a strong acid $(HCl)$ and a strong base $(NaOH)$,making it neutral $(pH = 7)$.$4$. $NaCN$ is a salt of a weak acid $(HCN)$ and a strong base $(NaOH)$,making it basic $(pH > 7)$.Thus,the increasing order of $pH$ is: $HCl < NH_4Cl < NaCl < NaCN$.

Arrange the following $0.1 \ M$ salt solutions in increasing order of their $pH$:

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