For a second-order reaction where the initial concentrations of both reactants are equal,it takes $3000 \ s$ for the reaction to be $60\%$ complete. How much time (in $s$) will it take for the reaction to be $20\%$ complete?

  • A
    $550$
  • B
    $280$
  • C
    $3030$
  • D
    $500$

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$iv. \ [A]=0.4, [B]=0.1$ $2.40 \times 10^{-2} \ M \ s^{-1}$

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