(A) The molar mass of oxalic acid dihydrate $(H_2C_2O_4 \cdot 2H_2O)$ is calculated as: $(2 \times 1) + (2 \times 12) + (4 \times 16) + 2 \times (2 \t

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(A) The molar mass of oxalic acid dihydrate $(H_2C_2O_4 \cdot 2H_2O)$ is calculated as: $(2 \times 1) + (2 \times 12) + (4 \times 16) + 2 \times (2 \times 1 + 16) = 2 + 24 + 64 + 36 = 126 \ g/mol$. Since oxalic acid is a dibasic acid,its n-factor is $2$. Equivalent mass = $\frac{\text{Molar mass}}{\text{n-factor}} = \frac{126}{2} = 63 \ g \ eq^{-1}$.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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What is the equivalent mass of oxalic acid $(H_2C_2O_4 \cdot 2H_2O)$?

A
$63$
B
$126$
C
$108$
D
$90$

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Atomic, Molecular and Equivalent masses

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What is the equivalent mass of oxalic acid $(H_2C_2O_4 \cdot 2H_2O)$?

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