The equivalent mass of a metal is 29.73 and t | vedclass

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(D) Given: Equivalent mass of metal $= 29.73$.Vapour density of metal chloride $= 130.4$.Molecular weight of metal chloride $= 2 	imes 	ext{Vapour d

Vedclass · Accepted Answer

$118.92$

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(D) Given: Equivalent mass of metal $= 29.73$.Vapour density of metal chloride $= 130.4$.Molecular weight of metal chloride $= 2 	imes 	ext{Vapour density} = 2 	imes 130.4 = 260.8$.Let the valency of the metal be $n$. The formula of the metal chloride is $MCl_n$.Molecular weight $= 	ext{Atomic weight of metal} + n 	imes 35.5$.Since $	ext{Atomic weight} = n 	imes 	ext{Equivalent mass}$,we have:$260.8 = n 	imes 29.73 + n 	imes 35.5$.$260.8 = n(29.73 + 35.5) = n(65.23)$.$n = \frac{260.8}{65.23} \approx 4$.Atomic weight of metal $= n 	imes 	ext{Equivalent mass} = 4 	imes 29.73 = 118.92$.

The equivalent mass of a metal is $29.73$ and the vapour density of its chloride is $130.4$. Find out the atomic mass of the metal.

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