What is the hybridization of carbon in graphite and diamond,respectively?
- A$sp, sp^2$
- B$sp^2, sp^3$
- C$sp^3, sp^2$
- D$sp^3, sp^3$
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Match the species in List-$I$ with their correct hybrid orbitals in List-$II$.
List-$I$ List-$II$ $(1)$ $SF_4$ $(A)$ $sp^3d^2$ $(2)$ $IF_5$ $(B)$ $d^2sp^3$ $(3)$ $NO_2^+$ $(C)$ $sp^3d$ $(4)$ $NH_4^+$ $(D)$ $sp^3$ $(E)$ $sp$
| List-$I$ | List-$II$ |
| $(1)$ $SF_4$ | $(A)$ $sp^3d^2$ |
| $(2)$ $IF_5$ | $(B)$ $d^2sp^3$ |
| $(3)$ $NO_2^+$ | $(C)$ $sp^3d$ |
| $(4)$ $NH_4^+$ | $(D)$ $sp^3$ |
| $(E)$ $sp$ |
Medium
View SolutionIn graphite,the $C$-atom is in which state of hybridisation?
Easy
View SolutionThe $C-C$ bond length of the following molecules is in the order:
MediumIIT 1991
View SolutionThe order of electronegativity of carbon in $sp$,$sp^{2}$ and $sp^{3}$ hybridised states follows:
Chlorine atom,in its third excited state,reacts with fluorine to form a compound $X$. The formula and shape of $X$ are :
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