Match the species in List-$I$ with their correct hybrid orbitals in List-$II$.

List-$I$	List-$II$
$(1)$ $SF_4$	$(A)$ $sp^3d^2$
$(2)$ $IF_5$	$(B)$ $d^2sp^3$
$(3)$ $NO_2^+$	$(C)$ $sp^3d$
$(4)$ $NH_4^+$	$(D)$ $sp^3$
	$(E)$ $sp$

(C) The hybridization is calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.
$(1)$ $SF_4$: $H = \frac{1}{2}(6 + 4) = 5 \rightarrow sp^3d$ (Matches $C$)
$(2)$ $IF_5$: $H = \frac{1}{2}(7 + 5) = 6 \rightarrow sp^3d^2$ (Matches $A$)
$(3)$ $NO_2^+$: $H = \frac{1}{2}(5 + 0 - 1) = 2 \rightarrow sp$ (Matches $E$)
$(4)$ $NH_4^+$: $H = \frac{1}{2}(5 + 4 - 1) = 4 \rightarrow sp^3$ (Matches $D$)
Correct matching: $(1-C, 2-A, 3-E, 4-D)$.