The order of electronegativity of carbon in $sp$,$sp^{2}$ and $sp^{3}$ hybridised states follows:

Oxidation of carbon with concentrated sulphuric acid gives the corresponding oxides of $C, S$ and $H$. The hybridisation of the central atoms in the oxides of $C$ and $H$ are respectively.

Considering the state of hybridization of carbon atoms,find out the molecule among the following which is linear?

The hybridisation of the central atom of $BF_3$,$SnCl_2$,and $HgCl_2$ respectively is:

The mean values for the radial distance for different phosphorus orbitals are $3s: 0.47 \ \mathring{A}$,$3p: 0.55 \ \mathring{A}$,$3d: 2.4 \ \mathring{A}$. When $P$ is going to form $PF_5$,then these radial distances are going to become arbitrarily . . . . . . , . . . . . . and . . . . . . respectively.

Consider the following reaction $BCl_3 + NH_3 \longrightarrow BCl_3 \cdot NH_3$. The geometries of $BCl_3$ and $BCl_3 \cdot NH_3$ respectively are