If {mu _0} and {varepsilon _0} denote the per | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The speed of light in free space is given by the relation: $c = \frac{1}{\sqrt{{\mu _0}{\varepsilon _0}}}$.Squaring both sides,we get: $c^2 = \fra

Vedclass · Accepted Answer

${L^{ - 2}}{T^2}$

Vedclass · Answer

(B) The speed of light in free space is given by the relation: $c = \frac{1}{\sqrt{{\mu _0}{\varepsilon _0}}}$.Squaring both sides,we get: $c^2 = \frac{1}{{\mu _0}{\varepsilon _0}}$.Therefore,the expression for the product is: ${\mu _0}{\varepsilon _0} = \frac{1}{c^2}$.Since the dimension of velocity $c$ is $[L{T^{ - 1}}]$,the dimensions of ${\mu _0}{\varepsilon _0}$ are:$[{\mu _0}{\varepsilon _0}] = \frac{1}{[L{T^{ - 1}}]^2} = \frac{1}{L^2 T^{-2}} = {L^{ - 2}}{T^2}$.

If ${\mu _0}$ and ${\varepsilon _0}$ denote the permeability and permittivity of free space,the dimensions of ${\mu _0}{\varepsilon _0}$ are:

Similar Questions

In a system,the unit of mass is $A \,kg$,length is $B \,m$,and time is $C \,s$. Then,the value of $10 \,N$ in this system is:

If $P, Q$ and $R$ are physical quantities having different dimensions,which of the following combinations can never be a meaningful quantity?

What is Dimensional Analysis? State the uses of Dimensional Analysis.

$E, m, L, G$ represent energy,mass,angular momentum,and gravitational constant respectively. The dimensions of $\frac{EL^2}{m^5 G^2}$ will be that of

If momentum $(P)$,area $(A)$,and time $(T)$ are taken to be fundamental quantities,then energy has the dimensional formula of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module