$\sim ((\sim p)\; \wedge q)$ is equal to
$p \vee (\sim q)$
$p \vee q$
$p \wedge (\sim q)$
$\sim p\; \wedge \sim q$
If the Boolean expression $( p \Rightarrow q ) \Leftrightarrow( q *(\sim p ))$ is a tautology, then the Boolean expression $p *(\sim q )$ is equivalent to
If $P$ and $Q$ are two statements, then which of the following compound statement is a tautology?
Negation of the compound proposition : If the examination is difficult, then I shall pass if I study hard
The conditional $(p \wedge q) \Rightarrow p$ is :-
The statement $[(p \wedge q) \rightarrow p] \rightarrow (q \wedge \sim q)$ is