$A$ current carrying circular loop of radius $2 \text{ cm}$ with unit normal $\hat{n} = \frac{\hat{i} + \hat{j}}{\sqrt{2}}$ is placed in a magnetic field $\vec{B} = B_0(3\hat{i} + 2\hat{k})$. If $B_0 = 4 \times 10^{-3} \text{ T}$ and current $I = 100\sqrt{2} \text{ A}$,the torque experienced by the loop is . . . . . . $\text{N}\cdot\text{m}$. $(\pi = 3.14)$

  • A
    $16 \times 10^{-5} \hat{k}$
  • B
    $5024 \times 10^{-7} \hat{k}$
  • C
    $5024 \times 10^{-7} \hat{i}$
  • D
    $5024 \times 10^{-7} \hat{j}$

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