(C) The torque acting on a current-carrying coil in a magnetic field is given by $\tau = N I A B \sin \theta$,where $\theta$ is the angle between the

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(C) The torque acting on a current-carrying coil in a magnetic field is given by $\tau = N I A B \sin \theta$,where $\theta$ is the angle between the normal to the plane of the coil and the magnetic field direction.Given: $N = 50$,$I = 2\, A$,$B = 0.2\, Wb/m^2$,and area $A = 0.12\, m \times 0.1\, m = 0.012\, m^2$.The plane of the coil is inclined at $30^{\circ}$ to the magnetic field,so the angle between the normal to the coil and the magnetic field is $\theta = 90^{\circ} - 30^{\circ} = 60^{\circ}$.Substituting the values: $\tau = 50 \times 2 \times 0.012 \times 0.2 \times \sin 60^{\circ}$.$\tau = 100 \times 0.0024 \times \frac{\sqrt{3}}{2} = 0.24 \times 0.866 = 0.2078\, Nm \approx 0.20\, Nm$.

Class 12 Physics Moving Charges and Magnetism Torque , Potential Energy and Work Done in Mangetic Field

Medium

$A$ rectangular coil of length $0.12\, m$ and width $0.1\, m$ having $50$ turns of wire is suspended vertically in a uniform magnetic field of strength $0.2\, Wb/m^2$. The coil carries a current of $2\, A$. If the plane of the coil is inclined at an angle of $30^{\circ}$ with the direction of the field,the torque required to keep the coil in this position will be .......$Nm$.

AIPMT 2015 All AIPMT

A
$0.12$
B
$0.15$
C
$0.20$
D
$0.24$

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Class 12

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Moving Charges and Magnetism

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Torque , Potential Energy and Work Done in Mangetic Field

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AIPMT 2015 Paper All AIPMT years →

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$A$ galvanometer coil has $500$ turns and each turn has an average area of $3 \times 10^{-4} \ m^{2}$. If a torque of $1.5 \ Nm$ is required to keep this coil parallel to the magnetic field when a current of $0.5 \ A$ is flowing through it,the strength of the magnetic field (in $T$) is:

MediumJEE MAIN 2020

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$A$ circular loop of radius $R$ carries a current $I$. Another circular loop of radius $r (r \ll R)$ carries a current $i$ and is placed at the centre of the larger loop. The planes of the two circles are at right angles to each other. Find the torque acting on the smaller loop.

$A$ current-carrying rectangular coil is placed in a uniform magnetic field. In which orientation will the coil not tend to rotate?

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$A$ galvanometer coil has $500$ turns and each turn has an average area of $3 \times 10^{-4} \ m^{2}$. If a torque of $1.5 \ Nm$ is required to keep this coil parallel to the magnetic field when a current of $0.5 \ A$ is flowing through it,the strength of the magnetic field (in $T$) is:

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