$\mathop {\lim }\limits_{x \to 0} \sin \left( {\frac{1}{x}} \right)$ क्या है?

  • A
    $0$
  • B
    $1$
  • C
    $-1$
  • D
    अस्तित्व में नहीं है

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$\lim _{x \rightarrow 0} \frac{(3^{2x}-\sqrt{x+1}) \sin 5x}{1-\cos 4x} =$

$\lim _{x \rightarrow 0} \frac{x^4+x^3+x^2}{\sin ^{-1}\left(\frac{x}{\sqrt{1+x^2}}\right) \cdot \tan ^{-1} x} = $

$\lim _{x \rightarrow 0} \frac{2x}{|x|+x^2} = $

वह द्विघात समीकरण जिसके मूल $m$ और $n$ हैं,जहाँ $m = \lim_{x \rightarrow 0} \frac{x \log(1+2x)}{x \tan x}$ और $n = \lim_{x \rightarrow 0} \frac{\log x + \log(\frac{1+x}{x})}{x}$ है,वह है

$\mathop {\lim }\limits_{x \to \infty } {\left( {1 + \frac{2}{x}} \right)^x} = $

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