$\lim _{x \rightarrow 0} \frac{(3^{2x}-\sqrt{x+1}) \sin 5x}{1-\cos 4x} =$

  • A
    $\frac{3}{5}(\log 18-1)$
  • B
    $\frac{5}{16} \log \left(\frac{81}{e}\right)$
  • C
    $\frac{4}{15}(\log 81-1)$
  • D
    $\frac{16}{5}[\log (27)-1]$

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$\mathop {\lim }\limits_{n \to \infty } \cos \left( {\frac{x}{2}} \right)\cos \left( {\frac{x}{4}} \right)\cos \left( {\frac{x}{8}} \right) \dots \cos \left( {\frac{x}{{{2^n}}}} \right)$ का मान क्या है?

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$\lim _{x}$ ${\rightarrow \infty} \frac{(2 x+1)^{50}+(2 x+2)^{50}+(2 x+3)^{50}+\cdots \cdots+(2 x+100)^{50}}{(2 x)^{50}+(10)^{50}} = \dots$

यदि $x$,$[0, 1]$ में एक वास्तविक संख्या है,तो $\lim_{m \to \infty} \lim_{n \to \infty} [1 + \cos^{2m}(n! \pi x)]$ का मान ज्ञात कीजिए।

$\lim _{x \rightarrow \infty} \frac{e^{x^4}-1}{e^{x^4}+1} = $

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