$\mathop {\lim }\limits_{x \to \infty } (\sqrt {{x^2} + 1} - x)$ ની કિંમત શોધો.

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    આમાંથી કોઈ નહીં

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જ્યારે $n$ પૂર્ણાંક હોય ત્યારે $\mathop {Lim}\limits_{n \to \infty } \cos \left( {\pi \sqrt {{n^2} + n} } \right)$ શોધો:

$\mathop {\lim }\limits_{n \to \infty } \left[ {\frac{1}{{{n^3} + 1}} + \frac{4}{{{n^3} + 1}} + \frac{9}{{{n^3} + 1}} + \dots + \frac{{{n^2}}}{{{n^3} + 1}}} \right] = $

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