mathop {lim }limits_{x to a} frac{{{x^2} - {a | vedclass

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Question

(C) આપણે બીજગણિતીય નિત્યસમ $x^2 - a^2 = (x - a)(x + a)$ નો ઉપયોગ કરીએ છીએ.$\mathop {\lim }\limits_{x 	o a} \frac{{{x^2} - {a^2}}}{{x - a}} = \mathop

Vedclass · Accepted Answer

$2a$

Vedclass · Answer

(C) આપણે બીજગણિતીય નિત્યસમ $x^2 - a^2 = (x - a)(x + a)$ નો ઉપયોગ કરીએ છીએ.$\mathop {\lim }\limits_{x 	o a} \frac{{{x^2} - {a^2}}}{{x - a}} = \mathop {\lim }\limits_{x 	o a} \frac{(x - a)(x + a)}{x - a}$કારણ કે $x 	o a$,તેથી $x - a 
eq 0$,તેથી આપણે $(x - a)$ પદને છેદ ઉડાડી શકીએ છીએ.$= \mathop {\lim }\limits_{x 	o a} (x + a) = a + a = 2a.$

$\mathop {\lim }\limits_{x \to a} \frac{{{x^2} - {a^2}}}{{x - a}} = $

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