A point source is placed at coordinates (0,1) | vedclass

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(A) Let the source be at $S(0,1)$ and the point on the mirror be $M$. The reflected ray passes through $P(3,3)$.Since the mirror is along the $X$-axis

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) Let the source be at $S(0,1)$ and the point on the mirror be $M$. The reflected ray passes through $P(3,3)$.Since the mirror is along the $X$-axis,the image of the source $S(0,1)$ formed by the mirror is $I(0,-1)$.The path length of the reflected ray is $SM + MP$.By the law of reflection,$SM = IM$.Therefore,the total path length is $IM + MP = IP$.The distance $IP$ is the distance between points $I(0,-1)$ and $P(3,3)$.Using the distance formula: $IP = \sqrt{(3-0)^2 + (3 - (-1))^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5$.

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