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(D) According to the law of reflection,the angle of incidence is equal to the angle of reflection.
At point $P$,the angle of incidence is $30^o$,so t

Vedclass · Accepted Answer

$60^o, 30^o, 60^o, 30^o$

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(D) According to the law of reflection,the angle of incidence is equal to the angle of reflection.
At point $P$,the angle of incidence is $30^o$,so the angle of reflection is $30^o$.
Since the walls are perpendicular,the angle of incidence at point $Q$ is $90^o - 30^o = 60^o$. Thus,the angle of reflection at $Q$ is $60^o$.
At point $R$,the angle of incidence is $90^o - 60^o = 30^o$. Thus,the angle of reflection at $R$ is $30^o$.
At point $S$,the angle of incidence is $90^o - 30^o = 60^o$. Thus,the angle of reflection at $S$ is $60^o$.
At point $T$,the angle of incidence is $90^o - 60^o = 30^o$. Thus,the angle of reflection at $T$ is $30^o$.
Therefore,the angles of reflection at $Q, R, S$ and $T$ are $60^o, 30^o, 60^o, 30^o$ respectively.

The following figure shows the multiple reflection of a light ray along a glass corridor where the walls are either parallel or perpendicular to one another. If the angle of incidence at point $P$ is $30^o$,what are the angles of reflection of the light ray at points $Q, R, S$ and $T$ respectively?

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