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(A) For a charged particle moving with velocity $v$ in a region with electric field $E$ and magnetic field $B$,the Lorentz force is $F = q(E + v 	ime

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electrons and protons with speed $\frac{|E|}{|B|}$ will pass through the slit

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(A) For a charged particle moving with velocity $v$ in a region with electric field $E$ and magnetic field $B$,the Lorentz force is $F = q(E + v 	imes B)$.For the particle to pass undeflected,the net force must be zero,i.e.,$qE = -q(v 	imes B)$.For a proton $(q > 0)$: The electric force $F_E = qE$ is downwards. The magnetic force $F_B = q(v 	imes B)$ is upwards (using the right-hand rule,$v$ is right,$B$ is out,so $v 	imes B$ is up). For no deflection,$qE = qvB$,which gives $v = E/B$.For an electron $(q However,the question asks for the behavior of the stream. Since both require the same speed $v = E/B$ to pass undeflected,option $B$ is incorrect as it implies electrons would not pass. Option $A$ is the correct statement.

$A$ stream of electrons and protons are directed towards a narrow slit in a screen (see figure). The intervening region has a uniform electric field $E$ (vertically downwards) and a uniform magnetic field $B$ (out of the plane of the figure) as shown. Then:

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