10^{20} photons of wavelength 660 nm are emi | vedclass

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Question

(A) The power $P$ of the lamp is given by the total energy emitted per second,which is the product of the number of photons emitted per second $N$ and

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) The power $P$ of the lamp is given by the total energy emitted per second,which is the product of the number of photons emitted per second $N$ and the energy of a single photon $E = \frac{hc}{\lambda}$.Given: $N = 10^{20} \ s^{-1}$,$\lambda = 660 \ nm = 660 	imes 10^{-9} \ m$,$h = 6.6 	imes 10^{-34} \ J \cdot s$,and $c = 3 	imes 10^8 \ m/s$.$P = N 	imes \frac{hc}{\lambda}$$P = 10^{20} 	imes \frac{6.6 	imes 10^{-34} 	imes 3 	imes 10^8}{660 	imes 10^{-9}}$$P = 10^{20} 	imes \frac{19.8 	imes 10^{-26}}{660 	imes 10^{-9}}$$P = 10^{20} 	imes 0.03 	imes 10^{-17}$$P = 30 \ W$.

$10^{20}$ photons of wavelength $660 \ nm$ are emitted per second from a lamp. The wattage of the lamp is (Planck's constant $h = 6.6 \times 10^{-34} \ J \cdot s$). (in $W$)

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