(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Given:$h = 6.63 \times 10^{-34} \, J \cdot s$$c = 3 \times 10^8 \, m/s$$\l

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Given:$h = 6.63 \times 10^{-34} \, J \cdot s$$c = 3 \times 10^8 \, m/s$$\lambda = 6840 \times 10^{-10} \, m$Using the relation $E(eV) = \frac{12400}{\lambda(\mathring{A})}$,we get:$E = \frac{12400}{6840} \, eV$$E \approx 1.81 \, eV$.

Class 12 Physics Dual Nature of Radiation and matter Particle Nature of Light : Photon

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What is the energy of a photon whose wavelength is $6840\,\mathring{A}$? (in $eV$)

AIIMS 2007 All AIIMS

A
$1.81$
B
$3.6$
C
$-13.6$
D
$12.1$

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Dual Nature of Radiation and matter

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Particle Nature of Light : Photon

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What is the energy of a photon whose wavelength is $6840\,\mathring{A}$? (in $eV$)

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The energy of a quantum of frequency $10^{15} \ Hz$ and $h = 6.6 \times 10^{-34} \ J \cdot s$ will be:

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