A planet is revolving around the Sun in an el | vedclass

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(A) According to Kepler's Second Law (Law of Areas),the radius vector joining the Sun and the planet sweeps out equal areas in equal intervals of time

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The time taken in travelling $DAB$ is less than that for $BCD$.

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(A) According to Kepler's Second Law (Law of Areas),the radius vector joining the Sun and the planet sweeps out equal areas in equal intervals of time.In the given figure,the Sun $(S)$ is at one of the foci of the elliptical orbit.The area swept by the planet in path $DAB$ is the area of the region bounded by the arc $DAB$ and the lines $SD$ and $SB$.The area swept by the planet in path $BCD$ is the area of the region bounded by the arc $BCD$ and the lines $SB$ and $SD$.Since the Sun is closer to the side $A$,the area swept by the planet in path $DAB$ is smaller than the area swept in path $BCD$.Therefore,the time taken to travel $DAB$ is less than the time taken to travel $BCD$.

$A$ planet is revolving around the Sun in an elliptical orbit as shown in the figure. Which of the following is a correct statement?

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