If the angular momentum of a planet of mass $m$, moving a round the Sun in a circular orbit its $L$, about the center of the Sun, its areal velocity is
$\frac{L}{m}$
$\frac{4L}{m}$
$\frac{L}{2m}$
$\frac{2L}{m}$
Two satellites $S_{1}$ and $S_{2}$ are revolving around a planet in the opposite sense in coplanar circular concentric orbits. At time $t=0$, the satellites are farthest apart. The periods of revolution of $S_{1}$ and $S_{2}$ are $3 \,h$ and $24 \,h$, respectively. The radius of the orbit of $S_{1}$ is $3 \times 10^{4} \,km$. Then, the orbital speed of $S_{2}$ as observed from
Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e. $F \propto {1\over r^3}$, but still remaining a central force. Then
If $L$ is the angular momentum of a satellite revolving around earth is a circular orbit of radius $r$ with speed $v$, then .........
The figure shows the motion of a planet around the sun in an elliptical orbit with sun at the focus. The shaded areas $A$ and $B$ are also shown in the figure which can be assumed to be equal. If ${t_1}$ and ${t_2}$ represent the time for the planet to move from $a$ to $b$ and $d$ to $c$ respectively, then
Match List$-I$ With List$-II$
$(a)$ Gravitational constant $(G)$ | $(i)$ $\left[ L ^{2} T ^{-2}\right]$ |
$(b)$ Gravitational potential energy | $(ii)$ $\left[ M ^{-1} L ^{3} T ^{-2}\right]$ |
$(c)$ Gravitational potential | $(iii)$ $\left[ LT ^{-2}\right]$ |
$(d)$ Gravitational intensity | $(iv)$ $\left[ ML ^{2} T ^{-2}\right]$ |
Choose the correct answer from the options given below: