$\frac{1}{2 \cdot 3} + \frac{1}{4 \cdot 5} + \frac{1}{6 \cdot 7} + \frac{1}{8 \cdot 9} + \dots$ is equal to

  • A
    $\log \left(\frac{2}{e}\right)$
  • B
    $\log \left(\frac{e}{2}\right)$
  • C
    $\log (2e)$
  • D
    $e - 1$

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