The position of a projectile launched from the origin at $t=0$ is given by $\vec{r}=(40 \hat{i}+50 \hat{j}) \text{ m}$ at $t=2 \text{ s}$. If the projectile was launched at an angle $\theta$ from the horizontal,then $\theta$ is (take $g = 10 \text{ m/s}^2$)

  • A
    $\tan^{-1} \frac{2}{3}$
  • B
    $\tan^{-1} \frac{3}{2}$
  • C
    $\tan^{-1} \frac{7}{4}$
  • D
    $\tan^{-1} \frac{4}{5}$

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